Математика, Детальна інформація

( b p(b

a 1/p = p(a

p(ag = ap/g

Eaaae\x00F0aoia \x00F0\x00B3aiyiiy:

ax(+bx+c=0; (a(0)

x1,2= (-b((D)/2a; D=b( -4ac

D>0( x1(x2 ;D=0( x1=x2

D<0, ei\x00F0ai\x00B3a iaia.

Oai\x00F0aia A\x00B3\x00BAoa:

x1+x2 = -b/a

x1( x2 = c/a

I\x00F0eaaaeaia eaaae\x00F0aoia \x00F0\x00B3aiyiiy:

x( + px+q =0

x1+x2 = -p

x1(x2 = q

sseui p=2k (p-/aoi.)

e x(+2kx+q=0, oi x1,2 = -k(((k(-q)

Eiaa\x00F0eoie:

loga x = b => ab = x; a>0,a(0

a loga x = x, logaa =1; loga 1 = 0

loga x = b; x=ab

loga b = 1/(log b a)

logaxy = logax + loga y

loga x/y = loga x - loga y

loga xk =k loga x (x >0)

logak x =1/k loga x

loga x = (logc x)/( logca); c>0,c(1

I\x00F0ia\x00F0an\x00B3?

A\x00F0eoiaoe/ia

an = an-1 +d